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where Therefore, H-Ay t (17) (18) (19) y=W =/ y=0 dv t dy y=0 6g*H vtdy (20) (21) itdy H>Ay p+-"60 te J Before equation 16 may be solved, two boundary conditions must be defined. The boundary conditions are: y=W t e y=0 pt-‘60 The first boundary condition (equation 20) was realized from the fact that the sum of all the differential currents in the electrolyte must be equal to the total cell current (I). The second boundary condition (equation 21) reflects the fact that the total cell current is carried in the chlorine electrode at y=0. The solution for the second order differential equation of the circuit element (equation 16) is in the general form of vfc = A* cosh(my) + B*sinh(my). (22) The constant m may be solved for by substituting the general form into equation 16. Differentiating the general form yields and dv -— = A'm*sinh(my) + B"m»cosh(my) (23) dv dy I t22 A-m •cosh(my) + B*m •sinh(my) 31-12PDF Image | Development of the Zinc-Chlorine Battery for Utility
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